Ответы к учебнику по математике за 2 класс 2 часть Рудницкая. Решение задач на увеличение и уменьшение в несколько раз. Номер №11

Вычисли.
(48 + 36) − 29
93 − (68 − 12)
36 + (20 + 8)
50 − (32 + 18)
63 + (28 − 8)
100 − (60 + 30)
100 − (60 − 30)
19 + (47 + 26)​​​​​​​
(63 : 9) + 54
62 − (7 * 8)
72 : (30 − 21)
6 * (100 − 94)

Ответ

(48 + 36) − 29 = 55
93 − (68 − 12) = 37
36 + (20 + 8) = 64
50 − (32 + 18) = 0
63 + (28 − 8) = 83
100 − (60 + 30) = 10
100 − (60 − 30) = 70
19 + (47 + 26)​​​​​​​ = 92
(63 : 9) + 54 = 61
62 − (7 * 8) = 6
72 : (30 − 21) = 8
6 * (100 − 94) = 36
Вычисления:
(48 + 36) − 29 = 84 − 29 = 55

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}48\\ 36\end{array}}\\ \begin{array}{r}84\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}84\\ 29\end{array}}\\ \begin{array}{r}55\end{array}\end{array}$
93 − (68 − 12) = 93 − 56 = 37

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}68\\ 12\end{array}}\\ \begin{array}{r}56\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}93\\ 56\end{array}}\\ \begin{array}{r}37\end{array}\end{array}$
36 + (20 + 8) = 36 + 28 = 64

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}20\\ 8\end{array}}\\ \begin{array}{r}28\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}36\\ 28\end{array}}\\ \begin{array}{r}64\end{array}\end{array}$
50 − (32 + 18) = 50 − 50 = 0

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}32\\ 18\end{array}}\\ \begin{array}{r}50\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}50\\ 50\end{array}}\\ \begin{array}{r}0\end{array}\end{array}$
63 + (28 − 8) = 63 + 20 = 83

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}28\\ 8\end{array}}\\ \begin{array}{r}20\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}63\\ 20\end{array}}\\ \begin{array}{r}83\end{array}\end{array}$
100 − (60 + 30) = 100 − 90 = 10

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}60\\ 30\end{array}}\\ \begin{array}{r}90\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}100\\ 90\end{array}}\\ \begin{array}{r}10\end{array}\end{array}$
100 − (60 − 30) = 100 − 30 = 70

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}60\\ 30\end{array}}\\ \begin{array}{r}30\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}100\\ 30\end{array}}\\ \begin{array}{r}70\end{array}\end{array}$
19 + (47 + 26)​​​​​​​ = 19 + 73 = 92

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}47\\ 26\end{array}}\\ \begin{array}{r}73\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}19\\ 73\end{array}}\\ \begin{array}{r}92\end{array}\end{array}$
(63 : 9) + 54​​​​​​​ = 7 + 54 = 61

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}7\\ 54\end{array}}\\ \begin{array}{r}61\end{array}\end{array}$
62 − (7 * 8)​​​​​​​ = 62 − 56 = 6

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}62\\ 56\end{array}}\\ \begin{array}{r}6\end{array}\end{array}$
72 : (30 − 21) = 72 : 9 = 8

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}30\\ 21\end{array}}\\ \begin{array}{r}9\end{array}\end{array}$
6 * (100 − 94) = 6 * 6 = 36

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}100\\ 94\end{array}}\\ \begin{array}{r}6\end{array}\end{array}$